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In this busy world everyone wants to save time. Being students, learning is our primary job. To save time, we need to learn faster. But how?
The first step is to have a SMART goal!
S – Specific
M – Measurable
A – Achievable
R – realistic
T – Time Bound
Having a Specific Measurable Achievable Realistic and Time Bound – SMART goal will increase your efficiency to grasp ideas faster.
While all of you may be having a long term goal, usually what you want to become after studies, you should have a short term goal, an objecting for every sitting of your studies too.
Have a Time Table – be specific what to study and when.
In the time slot for each, decide what and how much to study before you start. Know the outcome expected of you as a result of reading the portion. If it is not mentioned already, it is better to have a look at the questions based on the portion at hand before you actually read the topic.
Learn to read fast. Don’t go word by word while you read. Try to grasp a group of words at a go concentrating on the idea contained. Concentrate fully keeping in mind the objectives/ the questions you read based on the portion.
Do not reread or skip back until you have completed
After you have completed the reading check your comprehension by answering the questions.
Practice this daily and try to improve your reading and comprehension skills. This will certainly help you to score more as well as to live well in times to come.
I read in one of my chapters that when a body is immersed in a container of water (kept on a weighing machine which reads ‘W’ at first )the apparent weight lost by the body is equal to the buoyant force, and thus the reading ‘W’ increases.
Then I came across a question like this –
A beaker containing water kept on a weighing machine weighs W. A body of weight ‘w’ is dropped in it. It is floating & experiencing a buoyant force B, then the reading on machine is –
please give me the answer and explanation
the book says answer is (a)
but I think it is (c)
(Anwesha posted this questions)
The answer is A.
The total force acting downwards is W+w and the weighing scale is providing an equal reaction. the normal reaction offered by the weighing scale is what we get as the reading.
therefore the reading on the weighing scale must be W+w
The buoyant force is acting on the object dropped and is not contributing to the normal reaction offered by the weighing scale.
1. In first case we have the box with weight, say, 10 Newtons on incline. We calculate two components (perpendicular and parallel)of weight. We calculate normal force and force of friction. The box is at rest.
2. In second case we have ball on incline, made of same material as box from first case. Weight of the ball is the same as in first case, components of weight are the same as in first case. Normal force and friction have the same amount as in the case of box. But,unlike the box, ball is moving – it slides down. How’s that possible? If calculated net force is zero?
It is not true that the ball slides, but it will roll down.
In the first case, the forces balance each other and there is no motion.
In the second force, the frictional force acting tangentially backwards (up the incline) and the component of weight of the ball acting parallel to the plane and through the centre of the ball constitute a couple and tends to rotate it. Now there is no sliding; it rolls.
(If any further clarification is required please post as comment to this post)
Please refer to http://www.real-world-physics-problems.com/rolling-without-slipping.html for detailed treatment of the Physics of rolling without friction.