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## CENTRIPETAL FORCE MISCONCEPTION

For a circular motion centripetal force is required. Is there any other force which could replace centripetal force to obtain a circular motion? (Asked Sajin)

Please note that Centripetal Force is the net force that must be acting towards the centre of the circular path. It may be provided by one or more of the forces of different kinds. It is not a kind of force like the frictional force or gravitational force. In different cases the centripetal force is provided by different forces.

For example, when we whirl a stone tied to the end of a rope in a horizontal plane, the tension in the string provides the centripetal force. Here the real force acting is the tension in the string and its magnitude equals the centripetal force mv^2/r.

1. http://hyperphysics.phy-astr.gsu.edu/hbase/cf.html
2. http://en.wikipedia.org/wiki/Centripetal_force
3. http://www.physicsclassroom.com/Class/circles/u6l1c.cfm

## Stone falling in a well

“what is the distance a rock will fall in 5 seconds inside a well bore?”

Ans:

Using

$S=ut+\frac{1}{2}at^{2}$
and taking u = 0 (if falling from rest)
and g= 10 m/s2

S= 125 m

## A question from kinematics – motion in one dimension

“A stone is thrown in a vertically upward direction with a velocity of 5m/s. If the acceleration of the stone during its motion is 10m/s^2 in the downward direction , what will be the height attained by the stone and how much time will it take to reach there?”

Take,

u=5m/s

a= -10 m/s2

v=0 at the topmost position

S= Hmax = ?

The eqn of motion to use
v2 – u2 = 2aS
Which gives H = 1.25 m
From the eqn
v=u + at
t= 0.5 s

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