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Resistance and Resistivity

“Two wires A and B of equal lengths,different cross-sectional areas and made of same metal a)name the property which is same for both the wires. b)name the property which is different for both the wires”

Since both the wires are of same metal, the resistivity will be same for both whereas since the dimensions (Area of cross section here) are different, the resistance will be different

Amateur Research

Ask Physics is looking for students from Kendriya Vidyalayas of Kerala who are interested in doing Research in any branch of Science.

You will be contacted by the concerned official.

Optics

“when we exchange the lenses of compound microscope, then why it does not act as a telescope?”

Sequence of Learning Physics

In what sequence should these chapters be prepared for my exams:-
units and dimensions,kinematics,laws of motion,work power and energy,motion of system of particles and rigid body dynamics,gravitation.

It is better to follow the same pattern as given in NCERT text book

Problem from Kinematics

The speed of a train changes from36km/h to 72km/h in 10sec. calculate the distance travelled during this time

u=36km/h = 10 m/s

v=72 km/h=20 m/s

t=10 s

S=?

use v = u+ at to find a

a = 1 m/s2

Use v2-u2=2aS to find S

S = (400-100)/2 = 150 m

Ask Physics has installed the Latex server and now users can type latex code to insert complex equations to their comments or questions.

If you are not familiar with latex code, use the following site to generate the code for the equation that you need.

http://www.codecogs.com/latex/eqneditor.php

When you visit the above site you can edit and view the result of the code generate. You have the option to copy the image of the equation or to copy the code itself (what you typed for getting the image equation; not the html code supplied) and paste the code in your comment.

Go, Try it Now!
$(a+b)^{2}=a^{2}+b^{2}+2ab$

Find time of death of patient with differential equations

“The differential equation and solution for finding the time of death of a patient”