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A question from kinematics – motion in one dimension
Natasha Sehgal Asked:
“A stone is thrown in a vertically upward direction with a velocity of 5m/s. If the acceleration of the stone during its motion is 10m/s^2 in the downward direction , what will be the height attained by the stone and how much time will it take to reach there?”
Answer:
Take,
u=5m/s
a= -10 m/s2
v=0 at the topmost position
S= Hmax = ?
The eqn of motion to use
v2 – u2 = 2aS
Which gives H = 1.25 m
From the eqn
v=u + at
t= 0.5 s
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Physics Masters
Vivek Sawhney
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