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# Tag Archives: distance

## Physics behind pop up toys

I received a pop-ups popper toy (a rubber toy in the shape of a a dome). I noticed that when I load the popper on my finger, it launches a farther distance than if I load it on a table top. I thought the popper used a suction technique, but then I was confused as to why the popper went farther when loaded on my finger when there was little suction between the popper and my finger. Thanks!

Answers invited from visitors

## Spaceship and gravity – a problem

A spaceship is launched and starts moving directly towards the Moon. At what distance from the earth will the pull of the Moon on the spaceship exceed the pll of the Earth? Ignore the effect of the sun in this calculation

## Kinematics Numerical Problems

The velocity m, v m/s, of a particle is a straight line is given by

v = 6+pt+qt³

where t is the time in seconds after the particle passes through a fixed point O.

Given that t=2 s the distance of the particle from O is 16 m and its acceleration is 32m/s², calculate

a) the value of p and of q

b) the velocity of the particle at the instant when did acceleration is zero

## Question on distance, acceleration and velocity

Two cars start simultaneously form rest at the same place. one accelerate uniformly as 0.5m/s until it reaches a speed of 60m/s which it maintains steadily, the other accelarate uniformly at the speed of 80m/s which it maintained steadily. calculate

1. How many seconds will elapse before the cars are levelled and each travelling at equal speed.

2. the distance travelled by either car this time.

## Why Earth does not collide with the sun?

If our earth rotates around sun in discrete orbits, then why it doesn’t collide with Sun because of gravitational force acting between both bodies ?

**Answer**:

Earth is moving around the sun in such a way that the distance to be traveled TOWARDS sun is compensated by its circular motion. Therefore, instead of “falling towards” the sun, earth “falls around” and never reaches the sun.

## Restoring force and Newton’s law

We know that whenever a body is deformed a restoring force originates and tries to restore the shape of the body and according to newtons third law of motion whenever a force acts on a body an equal and opposite force acts on the other body . So is the restoring force an opposite reacton to the deforming force and if it is not then why do we consider its direction equal and opposite to the deforming force while solving problems .

(Asked Akshat )

**Answer**: Restoring force comes into play only when a deforming force is exerted. When no external force acts on a body, the molecules are in equilibrium. No net force acts on it. If an external force is applied on it, it will try to increase or decrease the intermolecular distance giving rise to a state of inequilibrium to teh molecules and they will tend to go back to their original positions to retain their state of equilibrium. This gives rise to the** RESTORING FORCE**.

Restoring force the the **internal** force that comes into play whenever an external force tries to change the inter-molecular distance. The restoring force at any instant (within limits) is equal in magnitude and opposite in direction to the deforming force

## A problem from Dimensional Analysis

if force F us given in terms of timeT and distance X f=AsinCT +BcosDX then the dimensions of A/B is equal to