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Numerical problem based on screw gauge

When a screw gauge with a LC of 0.01mm is used to measure the diameter of a

Screw Gauge
Screw Gauge

wire, the reading on the sleeve is found to be 0.5 mm and the reading on the thimble is found to be 27 division i)what is the diameter in cm?

Posted by Swati

Answer:

Diameter = PSR + CSR x LC = 0.5 +27 x 0.01 = 0.77 mm = 0.077 mm

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Schrodinger’s Cat in Daily Life

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