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When a high diver in a swimming event springs from the board and “tucks in”, a rapid spin result. Why is this?
The angular momentum of a body is the product of Moment of inertia (A measure of rotational inertia and it depends on the mass as well as distribution of mass about the axis of rotation. Farther the masses, greater will be the rotational inertia) and the angular velocity (The speed of rotation)
The angular momentum of a body remains unchanged in the absence of any external torque.
When the diver dives, he is giving his body a turning and takes off with his limbs stretched. In the stretched position, the moment of inertia is more. When he “tucks in”, the moment of inertia decreases. But since this happens without any external torque, it would result in an increase in angular velocity so as to keep the angular momentum constant.
Imagine a rod 2 meters long fixed at its center, 2 identical masses are placed 0.5 meters away on opposite sides , as the rod spins they slide towards the edges , according to the formula k.E.=0.5*I*ω2 the kinetic energy decreases , but since its a closed system why does the kinetic energy decrease ?
The decrease in KE accounted by the work done in displacing the masses
IN A PRISM DISPERSION OCCURS BUT NOT IN A GLASS SLAB PLEASE EXPLAIN ME CLEARLY WHY IN THE GLASS SLAB THE DISPERSION DOES NOT TAKES PLACE.
Answer: In a glass slab, the opposite sides are parallel. Though splitting up of light takes place inside the glass slab, the emergent rays are parallel to each other and enter simultaneously without any angular separation. But, in the case of a glass prism, the angular separation produced to the component colours due to refraction at the first face is further enhanced at the second face. Thus the angular separation between the emergent colours enables the viewer to see the colours separately and thus the dispersion is observed.
A small rubber wheel is used to drive a large pottery wheel. The two wheels are mounted so that their circular edges touch. The small wheel has a radius of 3.5 cm and accelerates at the rate of 7.9 rad/s^2, and it is in contact with the pottery wheel (radius 23.0 cm) without slipping.
a)Calculate the angular acceleration of the pottery wheel
b)Calculate the time it takes the pottery wheel to reach its required speed of 64 rpm
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