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Two stones of mass 5 kg and 10 kg are dropped from the same height above the ground level. Which one will hit the ground first? Why?
Answer: Both the stones will reach the ground simultaneously (provided we neglect the air resistance (the viscosity) and buoyant force.
This is because acceleration due to gravity is independent of mass of the freely falling body.
What is terminal speed? When a skydiver has reached terminal speed, what is the air resistance equal to? What is the skydivers acceleration?
A rifle at a height H aimed horizontally fires a bullet to the ground. At the same time , a bullet with the same mass in dropped from the same height. Neglecting air resistance, which one hits the ground first?Explain.
Both will hit the ground simultaneously.
When a body is projected horizontally, its initial vertical velocity is zero and vertical acceleration is g, the acceleration due to gravity.
The values of a velocity and acceleration of a freely falling body are also the same.
So, both will hit the ground simultaneously
A boy jumps from rest, straight down from the top of a cliff. He falls halfway down to the water below in 0.800 s. How much time passes during his entire trip from the top down to the water? Ignore air resistance.
let the total height be h
So, for first case
S = h/2
a = g=10 m/s^2
t = 0.8 sec
using the relation
h/2 = 0.5 x 10×0.8 ^2
In second case (considering the full motion)
using the relation
6.4 = 0.5 x 10 x t^2
t = 2 x 6.4/10 = 1.28 s
One side of the roof of a building slopes up at 33.5°. A roofer kicks a round, flat rock that has been thrown onto the roof by a neighborhood child. The rock slides straight up the incline with an initial speed of 15.0 m/s. The coefficient of kinetic friction between the rock and the roof is 0.430. The rock slides 10.0 m up the roof to its peak. It crosses the ridge and goes into free fall, following a parabolic trajectory above the far side of the roof, with negligible air resistance. Determine the maximum height the rock reaches above the point where it was kicked.
(The question is left for visitors to answer.)