From: venky
Subject: einstein’s theory of relativity

Message Body:
when two electrons leave a radioactive sample in opposite directions, each having a speed 0.67c
with respect to the sample, the speed of one electron relative to the other is
l.34c according to classical physics. What is the relativistic result?
We may regard one electron as the S-frame, the sample as the S’-frame,
and the other electron as the obje(‘t whose speed in the S-frame we seek . Then
u ‘ = 0.67c
v = 0.67c
and
u=
u ‘ + v = (0.67 + 0.67)c = 1.34 c = 0.92c.
1 + u ‘ v/c’2 1 + (0.67)2 1.45
The speed of one electron relative to the other is less than c.
but what if  one takes the other electron as the other frame(S’) ,in that case v=1.34c ,explain?