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If fundamental frequency of a closed pipe is 50 hz, then the frequency of the second overtone?

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1,656 views asked Aug 28, 2017 in Physics by daskulajit (120 points)

1 Answer

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Fundamental frequency of a closed pipe = v(sound) /4L
Given, = 50 Hz
v(sound) /4L =50Hz
Frequency of second overtone is :
= 5 {v(sound)/4L}
= 5 x fundamental frequency
= 5 x 50 Hz = 250 Hz
answered Sep 19, 2017 by giginailo (2,580 points)

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