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A particle is thrown with speed u at angle alpha with the

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A particle is thrown with speed u at angle alpha with the horizontal when the particle makes angle beta with horizontal it speed
asked Jul 29, 2017 in Physics by vaibhav_sharma (120 points)

1 Answer

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Initially,
u(x) = u cos (alpha)  and
u(y) = u sin (alpha)  
Say after time t it has velocity v making angle beta with horizontal.
Then
v(x) = u(x)  = u cos (alpha)  and
v(y) = v sin (beta) = u sin (alpha)  -  gt
Hence,
v= [(vx) ^2 + (vy) ^2]^1/2
=[u^2 +(gt) ^2 -2utsin (alpha)] ^1/2
Easy when you have t.
answered Sep 13, 2017 by giginailo (2,580 points)
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