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Find component of vector A along B and what is in question

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If vector A=2i + j & vector B=i - j sketch vectors graphically  & find component of vector A along vector B & perpendicular to vector B.
asked Jun 17, 2017 in Physics by kirtijaigupta (120 points)

1 Answer

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Angle between A and B is theta.
So cos theta =vector A. Vector B/ |A| |B|
Cos theta = (2 - 1)/(underroot 10)
= 1/(underroot 10)
Scalar Projection of A along B is :
|A| cos theta = (underroot 5)/(underroot 10)
=1/(underroot 2)
=0.707
Direction is same as that of B.
That is B cap = (1/underroot 2)(i-j)
Scalar projection perpendicular to B is: |A| sin theta
U may calculate it similarly. It's direction is (1/underroot 2)(i+j).
answered Sep 19, 2017 by giginailo (2,580 points)
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