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Distance covered by an object from origin in time t is given by x=t_6t^2+t^3,when the acceleration will be 0 ?

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asked May 23, 2017 in Physics by rithaghosh (120 points)

1 Answer

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If your equation is :
x= 6t^2 + t^3
Then first order derivative gives velocity that is :
V= 12t + 3t^2
Then second order derivative of x gives acceleration :
A = 12 + 6t
As given a =0
Then 12 + 6t =0 this gives t=(-2)
Negative sign can be ignored if question is mentioned specifically.
answered Sep 13, 2017 by giginailo (2,580 points)
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