The speed of a train changes from36km/h to 72km/h in 10sec. calculate the distance travelled during this time
Answer:
u=36km/h = 10 m/s
v=72 km/h=20 m/s
t=10 s
S=?
use v = u+ at to find a
a = 1 m/s2
Use v2-u2=2aS to find S
S = (400-100)/2 = 150 m
Home » Ask Physics » Problem from Kinematics
Problem from Kinematics
Physics Masters
Vivek Sawhney
AskPhysics Q&A
- Answered: How Quantum Field Theory explains triboelectricity?
- Answered: which theory state that every molecule of magnetic substance is a tiny magnet
- Answered: Why machine get jammed in winter?
- Answered: what is a laser?
- What do you mean by reversible and irreversible process
- Why do we Study electric field along axial line?
- Important topics to study for NEET Physics
- What are the most important topics in JAM Physics?
- If the size of the unit decreases by 20% the% change in the numerical value is
- Why is easier to hammer a sharp nail into wood than a blunt one?
You must log in to post a comment.