The speed of a train changes from36km/h to 72km/h in 10sec. calculate the distance travelled during this time
Answer:
u=36km/h = 10 m/s
v=72 km/h=20 m/s
t=10 s
S=?
use v = u+ at to find a
a = 1 m/s2
Use v2-u2=2aS to find S
S = (400-100)/2 = 150 m
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Problem from Kinematics
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