The speed of a train changes from36km/h to 72km/h in 10sec. calculate the distance travelled during this time

**Answer**:

u=36km/h = 10 m/s

v=72 km/h=20 m/s

t=10 s

S=?

use **v = u+ at** to find a

a = 1 m/s^{2}

Use **v ^{2}-u^{2}=2aS** to find S

S = (400-100)/2 = **150 m**