Two blocks A and B of mass m1 and m2 respectively are kept in contact on a frictionless table.The experimenter pushes the block A from behind so that the blocks accelerate. If the block A exerts a force F on the block B,what is the force exerted by the experimenter on A.

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# Numerical Problem from Motion of Connected systems

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- Motion on a frictionlessÂ surface https://t.co/VdoTuXiYoe

about 13 hours ago

sir, i think the force exerted by experimenter on ‘A’ is = F*(M1+M2)/M1

here are the details

given

force on B by A is F .

since it is a connected system acceleration “a” is

same.

so ,

a = F/m1 ——equa 1

we have the general equation F= ma

so the force excerted by the experimenter

is F’ = (m1 + m2)*F/m1 –( frm equa 1)

that is F’= F*( m1 + m2)/m1.