Two blocks A and B of mass m1 and m2 respectively are kept in contact on a frictionless table.The experimenter pushes the block A from behind so that the blocks accelerate. If the block A exerts a force F on the block B,what is the force exerted by the experimenter on A.
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Numerical Problem from Motion of Connected systems
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 Why do we take differential element “dx” from the origin at a distance “x” only? https://t.co/DDiTyByIA7
about 1 hour ago
sir, i think the force exerted by experimenter on ‘A’ is = F*(M1+M2)/M1
here are the details
given
force on B by A is F .
since it is a connected system acceleration “a” is
same.
so ,
a = F/m1 ——equa 1
we have the general equation F= ma
so the force excerted by the experimenter
is F’ = (m1 + m2)*F/m1 –( frm equa 1)
that is F’= F*( m1 + m2)/m1.