Numerical problem based on screw gauge
When a screw gauge with a LC of 0.01mm is used to measure the diameter of a
wire, the reading on the sleeve is found to be 0.5 mm and the reading on the thimble is found to be 27 division i)what is the diameter in cm?
Posted by Swati
Diameter = PSR + CSR x LC = 0.5 +27 x 0.01 = 0.77 mm = 0.077 mm