Home » Interesting Questions » Motion in one dimension Problem

Motion in one dimension Problem

The relation between time t and distance x is t = αx+ βx, where α & β are constants, then the retardation is

Sriyathmika asked


Given  t = αx2 + βx

Differentiate both sides with respect to time (t)
dt/dt = 2αx.dx/dt + β.dx/dt
1 = 2αxv + βv
v.(2αx + β) = 1
(2αx + β) = 1/v
Again differentiate both side with respect to time (t)
2α.dx/dt = -v -2 . dv/dt
2αv = v -2 . acceleration
acceleration = -2αv 3
Hence, retardation= 2αv 3

Visitors So Far @ AskPhysics

  • 2,046,756 hits

Subscribe to Blog via Email

Enter your email address to subscribe to this blog and receive notifications of new posts by email.

Join 4,001 other subscribers


  • FTL (Faster Than Light) Communication https://t.co/3crfAyliqK https://t.co/wjBxIwLR9e
    about 10 hours ago
%d bloggers like this: