Home » Interesting Questions » Motion in one dimension Problem

Subscribe to Blog via Email

Enter your email address to subscribe to this blog and receive notifications of new posts by email.

Join 3,803 other subscribers


Motion in one dimension Problem

Share with:

The relation between time t and distance x is t = αx+ βx, where α & β are constants, then the retardation is

Sriyathmika asked


Given  t = αx2 + βx

Differentiate both sides with respect to time (t)
dt/dt = 2αx.dx/dt + β.dx/dt
1 = 2αxv + βv
v.(2αx + β) = 1
(2αx + β) = 1/v
Again differentiate both side with respect to time (t)
2α.dx/dt = -v -2 . dv/dt
2αv = v -2 . acceleration
acceleration = -2αv 3
Hence, retardation= 2αv 3
%d bloggers like this: