Home » Ask Physics » EXCEEDING COSMIC LIMIT

### Subscribe to this site by email # EXCEEDING COSMIC LIMIT

“i’ve a beautiful doubt…normally we believe that nothing in dis world can cross cosmic limit…now suppose if 2 light particles(velocity=c) collide at right angles,,then their resultant will be [c*root2]…but that is greater than cosmic limit,right?????”

LET THE VISITORS RESPOND

1. Nick Grady says:

Yes and No. Two particles colliding (or any two objects) obey the rule of energy conservation. That is, the sum of the resultant energy cannot be more than the stored energy you start with. This is why fusion produces particles that obey the light speed maximum with surplus energy represented as heat, light, and other forms of radiation.

The correct formula would look approximately like E=m*c[squared] *2/velocity + E (residual) where residual is in the form of heat etc. By supposition of theorems one could calculate any given mass for any particle or reaction based on the resultants of a reaction. It also begs the question as to whether mass is in fact stored energy as a sum of the starting kinetic energy vectors. If Neutrons and electrons for instance were truly weightless then they would have to be non-existent, since energy is required to raise a particle to a given speed, then by kinetic theory the starting particle must have a mass to require the expenditure of energy to raise it to a certain state or (with kinetics) velocity. Hope this helps.

Which rather begs the question – has CERN got their sums correct? Because if mass is only attributable to the bosun, what happened to the energy expenditures of all the other particles. The main problem with modern quantum physics analysis is that it supposes zero energy = zero temperature, whereas for a moving particle in a vacuum energy is infinite when there is no opposing force. In this scenario, the hypothesis for speed in excess of light speed could be observed but no instrument is capable of measuring it since all instrumentation has to obey principles of the electromagnetic spectrum. You could theoretically calculate a velocity to energy by vectors, but would have no way of proving it unless you could physically travel at such speeds in a time-frame reference. The only modern instrument capable of exhibiting the required phenomenon, albeit at low energy levels, is a gyroscope.
The real clue is in the perception of what heat actually is. In an atom heat can only be transmitted by direct means. There is no heat in the spaces surrounding the particles since these spaces are in fact miniature vacuums. Once scientists model the relationship between heat energy as an expenditure of particles energy only by contact, mass calculations become far more straightforward. Electricity for instance is only the relative movement of two masses of energy with respect to each other along a defined path. Electricity will not flow if there is no energy level to which another energy level can reference itself IE a potential. I know this answer is quite involved, but should at least give you some lines along which to think about your idea.

2. Nick Grady says:

in follow up to my earlier answer it may help to understand that where energy levels represent a potential difference for the flow of electricity – gravity is the potential difference required for the movement of mass. Think about it.

This site uses Akismet to reduce spam. Learn how your comment data is processed.

### Hits so far @ AskPhysics

• 2,250,498 hits