I have one question friends –
If a rectangular loop is entering a perpendicular magnetic field then using Fleming right hand rule how will you explain the direction of induced current in the loop.
Pl explain how
(Mr. Nath posted)
Initially an emf will be developed across AD from D to A according to Fleming’s Right Hand Rule.
When the loop is completely inside the magnetic field, the emf across AD will be same as the emf across BC. Therefore, though CD is at a higher potential and AB is at a lower potential, no net current flows since the two emfs oppose each other equally.
(Vivekananda Sir said: Loop is moving inside the field so induced current will be in the direction DABCB.)