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Displacement Problem

A particle has a displacement of 12 m towards east and 5 m towards north and then 6 m vertically up. Find the magnitude of the resultant of these displacements.

The resultant of the first two displacements – 12 m and 5m in mutually perpendicular directions is

$\sqrt{\left&space;(&space;12^{2}+5^{2}&space;\right&space;)}=13$ m

The resultant of 13m and 6m in mutually perpendicular directions is

$\sqrt{\left&space;(&space;13^{2}+6^{2}&space;\right&space;)}=14.32&space;m$

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