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Displacement Problem

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A particle has a displacement of 12 m towards east and 5 m towards north and then 6 m vertically up. Find the magnitude of the resultant of these displacements.

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Answer:

The resultant of the first two displacements – 12 m and 5m in mutually perpendicular directions is

\sqrt{\left ( 12^{2}+5^{2} \right )}=13 m

The resultant of 13m and 6m in mutually perpendicular directions is

\sqrt{\left ( 13^{2}+6^{2} \right )}=14.32 m

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