Home » Ask Physics » Dimensional Analysis – A solved example

Dimensional Analysis – A solved example

Deduce the dimensional formula for workdone,pressure and density. [posted by boineelo ]

Answer:

workdone

We know that workdone = force x distance

Therefore [work done] =  [force] [distance]

but force = ma

[force]=[m][a]

[a]=[velocity]/[t]

[velocity]=[displacement]/[t]

So, putting all these together

[work done]=[m][distance][distance]/[time][time]

[work done]=ML2T-2

Similarly, you can work out the dimensional formula for pressure and density as

[pressure]=[force]/[area]=ML-1T-2

[density]=[mass]/[volume]=ML-3

Visitors So Far @ AskPhysics

  • 2,080,116 hits

Subscribe to Blog via Email

Enter your email address to subscribe to this blog and receive notifications of new posts by email.

Join 4,002 other subscribers

askphysics@Twitter

  • FTL (Faster Than Light) Communication https://t.co/3crfAyliqK https://t.co/wjBxIwLR9e
    about 2 months ago
%d bloggers like this: