Alpha particle and a proton are accelerated from rest by the same potential. Find the ratio of their de- broglie wavelength
(Asked by Amritha)
Answer:
Charge of alpha particle = 2e
Mass of alpha particle = 4 u
Charge of proton = e
mass of proton = u
The energy acquired by proton when accelerated through a pd of V,
E=eV
The momentum acquired by proton=
The de Broglie wavelength is given by
Therefore, de Broglie wavelength of Proton,
Similarly,
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