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Computer Science Sample Papers – Download and Practice

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Space-Time

I have been considering space-time and would like somebody smart to let me know if this is really dumb or not. I don’t know anything about Physics,
so I may be breaking a dozen rules with the thought, but I just have to put this out there.
1. Is there a ‘Frame Rate’ of the universe? (How many frames per second?)
2. Is the time between frames constant (ie. 1 light second between 1 frame to it’s next frame.)
3. (Simplified numbers here, I am a simpleton) Assuming a Constant time rate of 1 light minute between time frames…
If, in flat, space-time moveing truly zero miles per hour, there are 1 frames per minute, then it takes
10 frames to progress 10 minutes through time and the constant will always be 1 light minute. (Constant remains the
same under all circumstances)
When you move nearer to an immense object (A Black Hole), lets say 100 light miles away,
the number of frames doubles from 10 to 20 to span the same 10 minute time span, BUT the constant time between frames must stay the same.
So, from the original oberservers point of view, the participant is moveing more slowly through time (2 times longer to span the 10 minute.).
Move the scenerio half again closer to the Black Holes Singularity and the frames double again (20 frames to 40 frames).
So, again from the original observers point of view, the participant is moving even more slowly through time.
The time frame will continue to grow exponentially each time you move the participant closer to the singularity
This would mean that the participant would never be able to reach the singularity and, to the original observer, the participant would
seemingly become frozen in time.
This idea would allow for information falling into a black hole to not be destroyed, but rather simply beyond our ability to reach it.

The above idea works the same with speed. The faster you travel through space, the more frames between time spans you have. Thus
again, never allowing you to reach C (lightspeed).

Please let me know just how far away from reality my thought is.
Thank you for you time,
John Thatcher

How was CBSE Physics exam?

Hope that all have performed well in the CBSE Physics exam. If you found any problem with any of the questions or the pattern you may post your comments here.

Projectile motion – Problem

Hi. Can you help me please? I have trouble with this question:


An arrow is aimed horizontally, directly at a target 17.2 meters away. when the arrow is released, it lands 0.08 meters below the target point. How long was the arrow in the air? How fast was the arrow moving when it left the bow?Nadia asked

Answer

Consider vertical motion. Take y =1/2 gr^2=0.08m and find t

Considering horizontal motion, find Vx from the relation x =Vx t

Find Vy =gt

Find V =√{Vx^2+Vy^2}

String Theory

Can string theory be demonstrated? Is my understanding of the theory incorrect? I’d like to demonstrate the theory by using the strings of a guitar, so is string theory applicable, or should I focus more on pitch and harmonics?

Asked Brandon Dickey

Distance of closest approach

distance of closest approach

Work done and Kinetic/Potential Energy

Hi!

My Physics Class 11 question says that a climber who is 65kg climbs 600m. What is the work done by the climber?

I thought I would have to add both the change in KE and PE. But the answer says that you should simply use mgh (PE).

This is confusing because there should be some work done through movement. Why is KE omitted from calculating the work done that in this case?

Leo asked

Answer:

man climbing a treeMany problems in Physics are solved by making certain approximations and assumptions to avoid complications. If we consider all factors contributing towards the expenditure of energy there may still different factors, but of less importance for the problem under consideration.

In the question we assume that there is no change in Kinetic Energy involved. Work is not to be done to maintain the KE but to change the KE. Though there may be some changes in speed during the process, we disregard the changes and concentrate only on the change in potential energy, which is actually the work done against gravity.

Even if there is a change in Kinetic Energy, then also the work done against gravity will only be the change in potential energy (mgh). He may be doing work against friction and also the change his speed during the climbing process, but the work done against gravity would remain the same (mgh)

If the question had mentioned this (work done against gravitation) then confusion could have been avoided.

 

Hope that the idea is clear now. If you need further clarifications please respond via the comment form.

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  • Computer Science Sample Papers – Download and Practice https://t.co/KuDLKDqMw0
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