Please help me with the question below.. I’m totally confused!
A player throws a ball of mass 0.6 kg into the air, to a height of 4.0 m above the ground. The ball then falls to the ground. During the impact, 22% of the ball’s energy is lost. Calculate the height to which the ball rises after the bounce. Your assistance will be appreciated..
m= 0.6 kg
h = 4.0 m
Energy = mgh
During impact 22% energy is lost. Therefore, energy remaining = 88%
Therefore the energy with which the ball rebounds = 24 x 88/100 J
This is equal to the potential energy at the highest point after bouncing
If the new height is h’
mg h’ = 88% mgh
h’ = 0.88 x h = 0.88 x 4.0 =3.52 m
If you have further doubts, please ask
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