Home » Ask Physics » Bouncing ball and energy dissipation problem

Subscribe to Blog via Email

Enter your email address to subscribe to this blog and receive notifications of new posts by email.

Join 3,146 other subscribers

Archives

Bouncing ball and energy dissipation problem

Share with:


Please help me with the question below.. I’m totally confused!


Bouncing Ball - bad animation example

A player throws a ball of mass 0.6 kg into the air, to a height of 4.0 m above the ground. The ball then falls to the ground. During the impact, 22% of the ball’s energy is lost. Calculate the height to which the ball rises after the bounce. Your assistance will be appreciated..

Mustafa posted

Answer:

m= 0.6 kg

h = 4.0 m

Energy = mgh

During impact 22% energy is lost. Therefore, energy remaining = 88%

Therefore the energy with which the ball rebounds = 24 x 88/100 J

This is equal to the potential energy at the highest point after bouncing

If the new height is h’

mg h’ = 88% mgh

h’ = 0.88 x h = 0.88 x 4.0 =3.52 m

If you have further doubts, please ask


Comments

Ask a Doubt

Post your Physics Doubts here

Name (required)

Email (required)

Subject

Message/Doubt/Question

Upload a file if required

askphysics@Twitter

  • Visualisation paradox of tension https://t.co/7z63FA5Zxk https://t.co/ftxQzoVMvP
    about 3 weeks ago

Half Yearly Exam Count Down

Half Yearly Exam Count Down KVS Ernakulam RegionOctober 17, 2017
The Half Yearly Examination for Kendriya Vidyalayas of Kerala starts from 17 October 2017
%d bloggers like this: