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Zeen asks:

A boy jumps from rest, straight down from the top of a cliff. He falls halfway down to the water below in 0.800 s. How much time passes during his entire trip from the top down to the water? Ignore air resistance.

Answer :

let the total height be h

So, for first case

S = h/2

a = g=10 m/s^2

u=0 m/s

t = 0.8 sec

using the relation

h/2 = 0.5 x 10×0.8 ^2

h=6.4 m

In second case (considering the full motion)

S=h=6.4m

t=?

a=g=10m/s^2

u=o m/s

using the relation 6.4 = 0.5 x 10 x t^2

or

t = 2 x 6.4/10 = 1.28 s

Tags: 10m, air resistance, answer, ask Physics, Auto, Draft, physics, problem, relation, resistance, time, Water

here we have to use Newton’s equations of motion.

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here we have to use Newton’s equations of motion.