A black of mass 1.5kg placed on a rough horizontal surface is pulled by a constant horizontal force of 1.2kg wt. the cofficient of friction between the block and the surface is 0.3. Find acceleration produced in terms of g.
(Posted by Ankur Srivastava)
Answer:
Applied force, F=1.2 kg wt = 1.2g N (where g is the acceleration due to gravity)
Friction f=µmg=0.3 x 1.5 x g=0.45g N
The net force = ma
Therefore;
ma= F-f
=> 1.5 x a = 1.2 g -0.45g=0.8 g
or
a = (0.8/1.5)g
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