A black of mass 1.5kg placed on a rough horizontal surface is pulled by a constant horizontal force of 1.2kg wt. the cofficient of friction between the block and the surface is 0.3. Find acceleration produced in terms of g.

*(Posted by Ankur Srivastava)*

**Answer**:

Applied force, F=1.2 kg wt = 1.2g N *(where g is the acceleration due to gravity)*

Friction f=µmg=0.3 x 1.5 x g=0.45g N

The net force = ma

Therefore;

ma= F-f

=> 1.5 x a = 1.2 g -0.45g=0.8 g

or

**a = (0.8/1.5)g**

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