Natasha Sehgal Asked:

“A stone is thrown in a vertically upward direction with a velocity of 5m/s. If the acceleration of the stone during its motion is 10m/s^2 in the downward direction , what will be the height attained by the stone and how much time will it take to reach there?”

Answer:

Take,

u=5m/s

a= -10 m/s^{2}

v=0 at the topmost position

S= H_{max} = ?

The eqn of motion to use

v^{2} – u^{2} = 2aS

Which gives H = 1.25 m

From the eqn

v=u + at

t= 0.5 s