When an object is kept at a distance of 60cm from a concave mirror, the magnification is 1/2. Where should the object be placed to get magnification of 1/3??
please answer this question….
In the first part, u=-60, m=(-)1/2 implies v=-30 cm (Since the image must be real as concave lens form virtual image of bigger size only)
we get f = –20 cm
In II case
we get u=4f=4 x (-20)=-80 cm
(If this is not the expected answer please respond)