AK asks:
When an object is kept at a distance of 60cm from a concave mirror, the magnification is 1/2. Where should the object be placed to get magnification of 1/3??
please answer this question….
Ans:
In the first part, u=-60, m=(-)1/2 implies v=-30 cm (Since the image must be real as concave lens form virtual image of bigger size only)
Substituting in eqn 
or 
we get f = –20 cm
In II case
m=-1/3
v=u/3
f=-20cm
substituting in 
we get u=4f=4 x (-20)=-80 cm
(If this is not the expected answer please respond)
electricity question,
Q.1- A heating element of a hot plate on an electric cooking range draws 12 amperes from 240 V mains. How many kwh of energy will be consumed in one hour and 15 minutes
(A) 1.2
(B) 3.2
(C) 6.0
(D) 7.2