## Which books should be referred for IIT JEE ?

We have received hundreds of questions on the above subject. As the questions continue to pour in, we found it necessary to create a post on it.

IIT JEE is an entrance exam of international repute and IITs are considered at par with MIT by many. So, if you are an IIT aspirant, it is very much essential to prepare well in advance.

In this article we are focusing on Physics only

**Know the fundamentals**

Knowing the fundamentals is the first step. Learn your daily lessons well. In learning Physics, *“Questioning Every Answer is more important than Answering Every Question”*

Whenever you learn a new concept, try to get all the doubts clarified. Ask doubts and questions to your teachers. (If they don’t answer you satisfactorily, post them at www.askphysics.com )

Observe your surrounding and try finding examples on what you have learnt. The syllabus and books give you a framework on what to study; but don’t just limit your studies on books and syllabus. Search related information from real life and other sources of reference.

**RECOMMENDED BOOKS FOR IIT JEE PREPARATION**

The very first book you cannot avoid is the **NCERT TEXT BOOK for class XI and XII**

These books are designed after thorough research and the exercises are carefully added. Be sure to solve all the exercises including the **Additional Exercises**

Here are some of the Books you can refer for practicing for IIT JEE

- Concepts of Physics (by H C Verma)
- Fundamentals of Physics (by Resnick, Hallidey)
- University Physics (Zemansky)
- Problems in Physics (IE Irodov)

By the by, having too much books will be a hindrance. It is better to start with the NCERT books and after mastering all the exercises take up Resnick Hallidey and after clarifying the concepts take up Problems from H C Verma’s concepts of Physics and then go on to IRODOV if time allows.

Wish you all the best.

## A simple numerical on momentum

**Car mass is 1200 kg moving velocity is 108 km/hr. On applying brakes velocity reduced to 36 km/hr. Find change in momentum?**

*(posted by Aditi)*

Answer:

m=1200 kg

u=108 x 5/18=30m/s

v=36×5/18=10m/s

Change in momentum = m(v-u) = 1200 x (30-10)=1200 x 20= __24000 kg m/s__